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The work function of potassium is 3.0 eV. When it is illuminated by light of wavelength 3300A0 photo electrons are emitted. The stopping potential of photo electrons is [Plank's constant h=6.6×10-34Js, 1eV=1.6×10-19J, C = 3 ×108 ms-1]

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a

0.75 V

b

1.75 V

c

2.5 V

d

3.75 V

answer is A.

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Detailed Solution

KEmax=E−w =12,4003300−3.0 =3.75−3.0 =0.75ev =eV0 ⇒V0=0.75volt

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The work function of potassium is 3.0 eV. When it is illuminated by light of wavelength 3300A0 photo electrons are emitted. The stopping potential of photo electrons is [Plank's constant h=6.6×10-34Js, 1eV=1.6×10-19J, C = 3 ×108 ms-1]