First slide

Photoelectric effect and study of photoelectric effect

Question

The work function for sodium surface is 2.0 eV and that for aluminum surface is 4.2 eV. The two metals are illuminated with appropriate radiations so as to cause photoemission. Then

Easy

A

the threshold frequency for sodium will be less than that for aluminum
B

the threshold frequency of sodium will be more than that of aluminum
C

both sodium and aluminum will have the same threshold frequency
D

none of the above

Solution

As work function $W = h v_{0}$ , where $v_{0}$ is the threshold frequency.
Greater the work function, greater is the threshold frequency.
Therefore, the threshold frequency of sodium will be lesser than that for aluminum.

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