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Q.

The work functions of metals A and B are in the ratio 1 : 2. If light of frequenciesf and 2f are incident on metal surfaces of A and B respectively, the ratio of themaximum kinetic energies of photo electrons emitted is (f is greater then threshold frequency of A, 2f is greater than threshold frequency of B

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a

1 : 1

b

1 : 2

c

1 : 3

d

1 : 4

answer is B.

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Detailed Solution

hv=w+kE kE=hv−w kE=hf−w kE2=2hf−2w =2(hf−w) kE1kE2=12

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