The work of 146 kJ is performed in order to compress one kilo mole of a gas adiabatically and in this process the temperature of the gas increases by 7°C. The gas is:R=8.3 J mol-1K-1
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a
diatomic
b
triatomic
c
a mixture of monoatomic and diatomic
d
monoatomic
answer is A.
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Detailed Solution
in adiabatic process W=-nCV∆T ⇒ CV=1467=20.85=52R⇒Diatomic gas
The work of 146 kJ is performed in order to compress one kilo mole of a gas adiabatically and in this process the temperature of the gas increases by 7°C. The gas is:R=8.3 J mol-1K-1