First slide

Elastic behaviour of solids

Question

The work per unit volume to stretch the length by 1% of a wire with cross sectional area of 1 mm² will be. $[Y = 9 \times 10^{11} N / m^{2}]$

Moderate

A

$9 \times 10^{11} J$
B

$4.5 \times 10^{7} J$
C

$9 \times 10^{7} J$
D

$4.5 \times 10^{11} J$

Solution

$\begin{matrix} U = \frac{1}{2} \times Y \times (Strain)^{2} = \frac{1}{2} \times 9 \times 10^{11} \times {(\frac{1}{100})}^{2} \\ = 4 .5 \times 10^{7} J \end{matrix}$

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