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Q.

The work per unit volume to stretch the length by 1% of a wire with cross sectional area of 1 mm2 will be. [Y = 9×1011 N/m2]

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a

9×1011 J

b

4.5×107 J

c

9×107 J

d

4.5×1011 J

answer is B.

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Detailed Solution

U = 12×Y×(Strain)2 = 12×9×1011×(1100)2      = 4.5 × 107 J
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