First slide

Elastic Modulie

Question

The work per unit volume to stretch the length by 1% of a wire with cross sectional area of 1 ${mm}^{2}$ will be. $[Y = 9 \times 10^{11} N / m^{2}]$

Moderate

A

$9 \times 10^{11} J$
B

$4.5 \times 10^{7} J$
C

$9 \times 10^{7} J$
D

$4.5 \times 10^{11} J$

Solution

$U = \frac{1}{2} \times Y \times {(Strain)}^{2} = \frac{1}{2} \times 9 \times 10^{11} \times {(\frac{1}{100})}^{2}$
= 4.5 $\times 10^{7} J$

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