Q.
Write the expression for variation in time period of a pendulum clock due to thermal expansion
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a
ΔTT=12αΔt
b
ΔT=12αTΔt
c
T=12αΔt
d
None
answer is A.
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Detailed Solution
time period of simple pendulum is T=2πlg here l is length of the pendulum, g is acceleration due to gravity ⇒Tαl differentiate above equation ΔTT=12Δll---(1) as coefficient of linear expansion is α=ΔllΔtemperature ⇒αΔt=Δll---(2) substitute eqn(2) in eqn(1) ΔTT=12αΔt
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