Q.

Write the expression for variation in time period of a pendulum clock due to thermal expansion

Moderate

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ΔTT=12αΔt

ΔT=12αTΔt

T=12αΔt

None

answer is 1.

(Detailed Solution Below)

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Detailed Solution

time period of simple pendulum is T=2πlg here l is length of the pendulum, g is acceleration due to gravity ⇒Tαl differentiate above equation ΔTT=12Δll---(1) as coefficient of linear expansion is α=ΔllΔtemperature ⇒αΔt=Δll---(2) substitute eqn(2) in eqn(1) ΔTT=12αΔt

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