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Write the expression for variation in time period of a pendulum clock due to thermal expansion

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By Expert Faculty of Sri Chaitanya
a
ΔTT=12αΔt
b
ΔT=12αTΔt
c
T=12αΔt
d
None
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detailed solution

Correct option is A

time period of simple pendulum is T=2πlg here l is length of the pendulum,  g is acceleration due to gravity ⇒Tαl differentiate above equation ΔTT=12Δll---(1) as coefficient of linear expansion is α=ΔllΔtemperature ⇒αΔt=Δll---(2) substitute eqn(2) in eqn(1) ΔTT=12αΔt


Similar Questions

A clock pendulum made of invar has a period of 2s at 20oC. If the clock is used in a climate where average temperature is 40oC, what correction (in seconds) may be necessary at the end of 10 days to the time given by clock? αinvar =7×107 C1,1 day =8.64×104s

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