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Questions  

In X-ray tube, when the accelerating voltage V is halved, the difference between the wavelength of Kα line and minimum wavelength of continuous X-ray spectrum

a
remains constant
b
becomes more than two times
c
becomes half
d
becomes less than two times

detailed solution

Correct option is D

Δλ=λKα−λminWhen V is halved, λmin becomes two times but λKα remains the same.∴ Δλ′=λKα−2λmin =2(Δλ)−λKα∴ Δλ′<2(Δλ)

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