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Q.

The x-t graph of a particle undergoing simple harmonic motion is shown below.  The acceleration of the particle at t =43sec is

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a

332π2      cm/s2

b

−π232     cm/s2

c

π232cm/s2

d

−332π2cm/s2

answer is D.

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Detailed Solution

From the graph, time period, T = 8 sec.Equation of motion isx(cm)=(1cm)sin⁡2π8tv=π4cos⁡π4ta=−π42sin⁡π4t At t=43sec,a=−π216sin⁡π443=−332π2cm/s2.
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