Q.
At y = 1 cm, y = 3 cm y = 9 cm, y = 27 cm ... and so on, an infinite number of charges equal to 4C are placed. At x = 1 cm, x = 2 cm, x = 4 cm, x = 8 cm .... and so on, an infinite number of charges equal to – 4C are placed. Find the electric potential at origin in volts. (K=14πε0 )
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a
250 K
b
-200 K
c
Zero
d
100 K
answer is B.
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Detailed Solution
V1=kq1r1+1r2+1r3+......=k411×10-2+13×10-2+19×10-2+......=4k×10211-13=6k×102V2==kq1r1+1r2+1r3+......=-k412×10-2+14×10-2+18×10-2+......=-4k×10211-12=8k×102 V=V1−V2 =14π∈0[4×32−4×2]×102 =−200 k(k=14π∈0)
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