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Q.

Y=A sin(ωt+ϕ0) is the time –displacement equation of a SHM. At t=0 the displacement of the particle is  Y=A 2 and it is moving along negative  x-direction. Then the initial  phase angle ϕ0 will be:

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a

π3

b

2π3

c

π6

d

5π6

answer is D.

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Detailed Solution

y=Asin(ωt+ϕo),   at  t=0:  y=−A/2,   −A2=Asinϕo,   ϕo=5π6velocity is positive for  ϕo=π6 velocity is negaitive for  ϕo=5π6
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