$$y=x+x2+1x+1x3$$ Find dydx

Correct option is 11+2x−1x2−3x4

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$y = x + x^{2} + \frac{1}{x} + \frac{1}{x^{3}} Find \frac{d y}{d x}$

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detailed solution

Correct option is A

y=x+x2+1x+1x3dydx=dxdx+dx2dx+dx-1dx+dx−3dx=1+2x+−1x−1−1+−3x−3−1 −dxdx=1,dxndx=nxn−1=1+2x−1x2−3x4

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y=x+x2+1x+1x3 Find dydx

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$y = x + x^{2} + \frac{1}{x} + \frac{1}{x^{3}} Find \frac{d y}{d x}$