First slide

Projection Under uniform Acceleration

Question

Y-component of velocity is 20 and X-component of velocity is 10. The direction of motion of the body with the horizontal at this instant is

Easy

A

$\tan^{- 1} (2)$
B

$\tan^{- 1} (1 / 2)$
C

$45^{\circ}$
D

$0^{\circ}$

Solution

We know that
$\begin{array}{l} \tan θ = \frac{vertical component of velocity}{horizontal component of velocity} \\ = \frac{V_{y}}{V_{x}} \\ or \tan θ = \frac{20}{10} = 2 or θ = \tan^{- 1} (2) \end{array}$

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