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Q.

In YDSE double slit experiment, one of the slit wider than other, so that the amplitude of the light from one slit is thrice of that from the other slit. If I0 be the maximum intensity. Then find the resultant intensity I when the interference at a phase difference 1200.

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a

1316I0

b

78l0

c

138I0

d

716l0

answer is D.

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Detailed Solution

Let A1=A0,A2=3A0 Then Amax2=A02+9A02+2A0⋅3A0=16A02Amax=4A0…(i) For ϕ=120A2=A02+9A02+2A0⋅3A0cos⁡120∘=10A02−3A02=7A02A=7A0 …(ii)1Imax=1I0=7A0216A02I=716I0

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In YDSE double slit experiment, one of the slit wider than other, so that the amplitude of the light from one slit is thrice of that from the other slit. If I0 be the maximum intensity. Then find the resultant intensity I when the interference at a phase difference 1200.