First slide

In YDSE one of the slits is covered with a thin transparent sheet

Question

In a YDSE, each slit has a width b and maximum intensity at a point on the screen is I. In another YDSE, the slits have widths b and b/4. Then maximum intensity obtained on the screen will be

Moderate

A

$\frac{3 I}{2}$
B

$\frac{16 I}{25}$
C

$\frac{9 I}{16}$
D

$\frac{9 I}{4}$

Solution

(3)
In the first experiment, if intensity of light emerging from each slit be $I_{0},$ then
$I_{m a x} = I = 4 I_{0} .$
In the second experiment, intensity of light emerging from the slit of width b is $I_{0},$ and that from the slit of width b/4 is $\frac{I_{0}}{4} .$
$∴ {I^{'}}_{\max} = {(\sqrt{I_{0}} + \sqrt{\frac{I_{0}}{4}})}^{2} = \frac{9}{4} I_{0} = \frac{9}{4} \times \frac{I}{4} = \frac{9 I}{16}$

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