In a YDSE, each slit has a width b and maximum intensity at a point on the screen is I. In another YDSE, the slits have widths b and b/4. Then maximum intensity obtained on the screen will be

(3)In the first experiment, if intensity of light emerging from each slit be I0, then Imax=I=4I0.In the second experiment, intensity of light emerging from the slit of width b is I0, and that from the slit of width b/4 is I04.∴  I'max=I0 +  I042=94 I0=94 ×  I4=9I16