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Q.

In YDSE intensity on the screen at a distance y from the centre of central bright fringe is found to be 25% of maximum intensity of bright fringe. If β be the fringe width, then yβ is

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a

13

b

23

c

34

d

14

answer is A.

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Detailed Solution

I=Im cos2ϕ2⇒Im4=Imcos2 ϕ2⇒ϕ2=π3Now, ϕ2=πλ x d sinθ=πλd tanθ=πλd.yD=πyβ∴πyβ=π3⇒yβ=13
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