In YDSE, the two slits are separated by 0.1 mm and they are 0.5 m from the screen. The wavelength of light used is 5000 Å. Distance between 7th and 4th maxima
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a
8.75 mm
b
7.5 mm
c
8 mm
d
10 mm
answer is B.
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Detailed Solution
Dy=y(7) bright −y(4) dark =7λDd−4λDd=3λDd=3×5000×10−10×0.510−4⇒3×5×0.5×10−7+4⇒7.5×10−3m=7.5mm