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In YDSE, the two slits are separated by 0.1mm and they are 0.5m from the screen. The wavelength of light used is 5000A0. Find the distance of 11th dark from the central maximum of the screen.

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answer is 3.

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Detailed Solution

yndark=2n−1λD2dy11=21×5×10−7×0.52×10−4=26.25 mm

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