You are given several identical resistances each of value $$-R=10$$Ω and each capable of carrying a maximum current of one ampere. It is required to make a suitable combination of these resistances of $$5$$Ω which can carry a current of $$4$$ ampere. The minimum number of resistances of the type R that will be required for this job is

Question

You are given several identical resistances each of value $$-R=10$$Ω and each capable of carrying a maximum current of one ampere. It is required to make a suitable combination of these resistances of $$5$$Ω which can carry a current of $$4$$ ampere. The minimum number of resistances of the type R that will be required for this job is

Infinity Learn · Accepted Answer

To carry a current of $$4$$ amperes, we need four paths, each carrying a current of one ampere, Let r be the resistance of each path. These are connected in parallel. Hence their equivalent resistance will be r $$/$$ $$4$$. According to the given $$problemr4=5$$  or  $$r=20$$ΩaFor this purpose two resistances should be connected. There are four such combinations. Hence, the total number of resistances $$=$$ $$4x$$ $$2=$$ $$8$$

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