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Q.

In young double slit experiment, The light incident on the slits contains two lights having wavelengths λ1 and λ2. If 4th maxima of  λ1 coincides with third minima of  λ2 and  β1 and β2 be the fringe widths of λ1 and λ2 respectively, Then

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a

β1=β2

b

β1>β2

c

β1<β2

d

Informations are not sufficient to find the relation between β1 and β2

answer is C.

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Detailed Solution

4λ1Dd=2+12λ2Dd⇒λ1λ2=58Since β=λDd and λ1<λ2,we can conclude, β2>β1
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