First slide
Coherent sources and their importance in interference
Question

In young double slit experiment λ=500nm,d=1mm and D=1m .The minimum distance from the central maximum where intensity is half of the maximum intensity is (assume intensity from each slit is same) 

Moderate
Solution

Given Wavelength  λ=500 nm=5×107 m
Distance between two slits  d=1 mm=103 m
Distance between slits and screen  D=1 m
Maximum intensity  =4I0
I=4Iocos2ϕ2

2Io=4Iocos2ϕ2

cosϕ2=12

ϕ=π2

Path difference Δϕ=2πλΔx

Δx=λ4

y=Δx.Dd=λD4d=5×107×14×103=1.25×104 m

Get Instant Solutions
When in doubt download our app. Now available Google Play Store- Doubts App
Download Now
Doubts App