Questions
In Young's double slit arrangement, let be the fringe width and let Io be the intensity at the central bright fringe. At a distance x from the central bright fringe, the intensity will be
detailed solution
Correct option is C
Path difference = x (d /D ) where d is the separation between two sources and D is the distance of screen from two sources. Phase differenceϕ=2πλ×xdD ⇒φ2=πxβIntensity at a distance x from the central bright fringe is given by I = I0 cos2 φ2=I0 cos2 πxβTalk to our academic expert!
Similar Questions
In Young's double slit experiment intensity of light emerging from each slit is I0. Wavelength of light used is , separation between the slits is d and separation between the slits and screen is D. P is a point on the screen where the resultant intensity is 3I0. Then the minimum path difference between rays emerging from the slits at point P is
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