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Q.

In Young’s double slit experiment, the aperture screen distance is 2m. The fringe width is 1 mm. Light of 600 nm is used. If a thin plate of glass (μ = 1.5) of thickness 0.06 mm is placed over one of the slits, then there will be a lateral displacement of the fringes by

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a

0 cm

b

5 cm

c

10 cm

d

15 cm

answer is B.

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Detailed Solution

Lateral displacement of fringes = βλ(μ−1)t=1×10−3600×10−9(1.5−1)×0.06×10−3=120m=5cm
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