First slide

Young's double slit Experiment

Question

In Young's double slit experiment, the aperture screen distance is 2 m. The fringe width is 1 mm. Light of 600 nm is used. If a thin plate of glass $(μ = 1 .5)$ of thickness 0.06 mm is placed over one of the slits, then there will be a lateral displacement of the fringes by

Moderate

A

0 cm
B

5 cm
C

10 cm
D

15 cm

Solution

Lateral displacement of fringes $= \frac{β}{λ} (μ - 1) t$
$= \frac{1 \times 10^{- 3}}{600 \times 10^{- 9}} (1 .5 - 1) \times 0 .06 \times 10^{- 3}$
$= \frac{1}{20} m = 5 cm .$

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