In Young's double slit experiment, carried out with light of wavelength A = 5000 $\overset{0}{A}$ tif the distance between the third minima on the either side of the central maxima is 25mm and the screen is at 200 cm from the slits. then the distance between the slits is

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in Young's double slit  experiment if the fringe width is β then the distance between the  first two minima on the either side of the central maxima is β then separation between the second minima on the either side of the central maxima is $$3$$ β  and between third minima on either side is $$5$$βSo $$5$$β $$=25$$ mm  β $$=$$ $$5mm$$λ$$Dd=5$$×$$10-3d=$$λ$$D5$$×$$103=5$$×$$10-7$$×$$25$$×$$103=2$$×$$10-4$$

In Young's double slit experiment, carried out with light of wavelength A = 5000 $\overset{0}{A}$ tif the distance between the third minima on the either side of the central maxima is 25mm and the screen is at 200 cm from the slits. then the distance between the slits is

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In Young's double slit experiment, carried out with light of wavelength A = 5000 A0 tif the distance between the third minima on the either side of the central maxima is 25mm and the screen is at 200 cm from the slits. then the distance between the slits is

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In Young's double slit experiment, carried out with light of wavelength A = 5000 $\overset{0}{A}$ tif the distance between the third minima on the either side of the central maxima is 25mm and the screen is at 200 cm from the slits. then the distance between the slits is