Q.

In a Young’s double slit experiment d=1 mm, λ=6000A0 and D=1 m (where d, λ and D have usual meaning). Each of slit individually produces the same intensity on the screen. Then select the correct option(s).

Moderate

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By Expert Faculty of Sri Chaitanya

The minimum distance between two points on the screen having 75% intensity of the maximum intensity is 0.2 mm

The minimum distance between two points on the screen having 75% intensity of the maximum intensity is 20 μm

Fringe width is 0.6 mm

Fringe width is 0.3 mm

answer is 1,3.

(Detailed Solution Below)

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Detailed Solution

β=Dλd=1×6000×10-1010-3=0.6 mmPhase difference between centre and any point is ϕThen Iϕ=4I0cos2ϕ2 ⇒344I0=4I0cos2ϕ2cosϕ2=±32 ⇒ϕ2=π6⇒ϕ=π3 ∴ minimum distance between such points =2y=2DΔxd=2DΔϕλd2π=21π36000×10-1010-32π=0.2mm

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