In Young's double slit experiment, the distance between the slits is 1 mm and that between slit and screen is 1 meter and 10th fringe is 5 mm away from the central bright fringe, then wavelength of light used will be
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a
5000Å
b
6000Å
c
7000Å
d
8000Å
answer is A.
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Detailed Solution
By using xn=nλDd ⇒5×10−3=10×λ×11×10−3⇒λ=5×10−7m=5000 A0