In Young's double slit experiment the distance between the slits is 1 mm. Find the width of each slit of YDSE setup so that 10th maxima of the double slit pattern is within the central maximum of the single slit pattern?
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a
0.9 mm
b
0.8 mm
c
0.2 mm
d
0.6 mm
answer is C.
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Detailed Solution
The angular separation between n bright fringes, θn=xnD=nλd Fringes, θn=xnD=nλd For 10 bright fringes, θ10=10λdThe angular width of the central maximum in the diffraction pattern due to slit of width a is2θ1=2λa Now 10λd≤2λa or a≤d5=15mn=0.2mn