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Q.

In Young's double slit experiment the distance between the slits is 1 mm. Find the width of each slit of YDSE setup so that 10th maxima of the double slit pattern is within the central maximum of the single slit pattern?

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a

0.9 mm

b

0.8 mm

c

0.2 mm

d

0.6 mm

answer is C.

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Detailed Solution

The angular separation between n  bright fringes, θn=xnD=nλd Fringes, θn=xnD=nλd For 10 bright fringes, θ10=10λdThe angular width of the central maximum in the diffraction pattern due to slit of width a is2θ1=2λa Now 10λd≤2λa or a≤d5=15mn=0.2mn
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