First slide

Young's double slit Experiment

Question

In Young's double slit experiment the distance between the slits and the screen is doubled. The separation between the slits is reduced to half. As a result the fringe width

Easy

A

is halved
B

becomes four times
C

remains unchanged
D

is doubled

Solution

$Fringe width, β = \frac{λ D}{d}$
where D is the distance between slits and screen and d is the distance between the slits. When D is doubled and d is reduced to half, then fringe width becomes
$β^{'} = \frac{λ (2 D)}{(d / 2)} = \frac{4 λ D}{d} = 4 β$

Get Instant Solutions

When in doubt download our app. Now available Google Play Store- Doubts App

Recieve an sms with download link

Doubts App

OR

SCAN ME

Doubts App

Doubts App