In young's double slit experiment the distance between the sources is 7.7 μm . If the wavelength of light used is 500 nanometre, the angular position of the six dark fringe from the centre fringe is
see full answer
Your Exam Success, Personally Taken Care Of
1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya
a
0.357 rad
b
0.92 rad
c
0.15 rad
d
3.57 rad
answer is A.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
Distance between the slits d=7.7 μm=7.7×10−6 m Wavelength λ=500 nm=500×10−9 m Number of fringes n=6 Angular position θ=(2n−1)λ2d = (2×6−1) ×500 × 10−92 × 77 × 10−7 = 11×52×777 =0.357 rad