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Q.

In Young's double slit experiment, the distance between sources is 1 mm and distance between the screen and source is 1 m. If the fringe width on the screen is 0.06 cm, then λ =

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a

6000Å

b

4000Å

c

1200Å

d

2400Å

answer is A.

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Detailed Solution

β=λDd⇒0.06×10−2=λ×11×10−3⇒λ=6000 A0
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In Young's double slit experiment, the distance between sources is 1 mm and distance between the screen and source is 1 m. If the fringe width on the screen is 0.06 cm, then λ =