First slide

Coherent sources and their importance in interference

Question

In Young's double slit experiment, the distance between the two slits is 0.1 mm and the wavelength of light used is $4 \times 10^{- 7} m$ . If the width of the fringe on the screen is 4 mm, the distance between screen and slit is

Easy

A

0.1 mm
B

1 cm
C

0.1 cm
D

1 m

Solution

$β = \frac{λD}{d} \Rightarrow (4 \times 10^{- 3}) = \frac{4 \times 10^{- 7} \times D}{0 .1 \times 10^{- 3}} \Rightarrow D = 1 m$

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