Q.

In Young's double slit experiment, the distance between two slits that results in the third minimum for 420 nm violet light at the angle of 30o, is

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a

8.4×10−3mm

b

6.8×10−3mm

c

2.1×10−3mm

d

4.2×10−2mm

answer is C.

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Detailed Solution

For third minimum, dsin⁡30o=(2+12)4200 Ao⇒d=2.1×10−3mm
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