In Young's double slit experiment, the distance between two sources is 0.1 mm. The distance of screen from the sources is 20 cm. Wavelength of light used is 5460 Å Then angular position of the first dark fringe is
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a
0.080
b
0.160
c
0.200
d
0.3130
answer is D.
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Detailed Solution
Angular position of first dark fringeθ=λ2d=5460×10−102×0.1×10−3×180π (in degree) =0.156∘