First slide

Young's double slit Experiment

Question

In Young's double slit experiment, the distance between two sources is 0.1 mm. The distance of screen from the sources is 20 cm. Wavelength of light used is $5460 Å$ Then angular position of the first dark fringe is

Easy

A

0.08⁰
B

0.16⁰
C

0.20⁰
D

0.313⁰

Solution

Angular position of first dark fringe
$θ = \frac{λ}{2 d} = \frac{5460 \times 10^{- 10}}{2 \times 0 .1 \times 10^{- 3}} \times \frac{180}{π} (in degree)$
$= {0.156}^{\circ}$

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