First slide

Young's double slit Experiment

Question

In Young's double slit experiment, the fringe width is $β$ . If the entire arrangement is now placed in a liquid of refractive index $μ$ , the fringe width becomes

Easy

A

$μ$ B
B

$\frac{β}{μ}$
C

$\frac{β}{(μ + 1)}$
D

$\frac{β}{(μ - 1)}$

Solution

we know that $β = \frac{λD}{(2 d)}$ where 2 d is distance between two slits. When the arrangement is placed inside a liquid of refractive index $υ$ .let new fringe width becomes $β$ Remembering that in liquid, the wavelength is reduced
$by λ / μ, we have β^{'} = \frac{(λ / μ) D}{2 d} = \frac{1}{μ} [\frac{λD}{2 d}] = \frac{β}{μ}$

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