In Young’s double slit experiment, the fringes are displaced by a distance x when a glass plate of refractive index 1.5 is introduced in the path of one of the beams. When this plate in replaced by another plate of the same thickness, the shift of fringes is (3/2)x. The refractive index of the second plate is
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a
1.75
b
1.50
c
1.25
d
1.00
answer is A.
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Detailed Solution
Shift x on the screen is given by, x=μ−1tDd For first plate, x=μ1−1tDd For second plate, 32x=μ2−1tDd After dividing, μ2−1μ1−1=32 ⇒μ2−11.5−1=32 ⇒μ2=1.75