In Young's double slit experiment, if the slit widths are in the ratio 1 : 9, then the ratio of the intensity at minima to that at maxima will be

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1/9

1/4

1/3

answer is C.

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Detailed Solution

Slit width ratio = 1 : 9Since slit width ratio is the ratio of intensity and intensity∝ (amplitude)2∴I1:I2=1:9⇒a12:a22=1:9⇒a1:a2=1:3Imax=(a1+a2)2, Imin=(a1−a2)2⇒IminImax=14

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