In a Young’s double slit experiment, if there is no initial phase difference between the light from the two slits, a point on the screen corresponding to the fifth minimum has path difference
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a
11λ2
b
5λ2
c
10λ2
d
9λ2
answer is D.
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Detailed Solution
Path difference for destructive interference in YDSE⇒Δxn=(2n-1)2λ n=1,2,3… ΔX5th=2×5-12λ=9λ2