In a Young’s double slit experiment, if there is no initial phase difference between the light from the two slits, a point on the screen corresponding to the fifth minimum has path difference

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11λ2

5λ2

10λ2

9λ2

answer is D.

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Detailed Solution

Path difference for destructive interference in YDSE⇒Δxn=(2n-1)2λ n=1,2,3… ΔX5th=2×5-12λ=9λ2

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