First slide

Coherent sources and their importance in interference

Question

In Young's double slit experiment, if the widths of the slits are in the ratio 4 : 9, the ratio of the intensity at maxima to the intensity at minima will be

Easy

A

169 : 25
B

81 : 16
C

25 : 1
D

9 : 4

Solution

$Slit width ratio = 4 : 9; hence I_{1} : I_{2} = 4 : 9 ∴ \frac{a_{1}^{2}}{a_{2}^{2}} = \frac{4}{9} \Rightarrow \frac{a_{1}}{a_{2}} = \frac{2}{3} ∴ \frac{I_{max}}{I_{min}} = \frac{{(a_{1} + a_{2})}^{2}}{{(a_{1} - a_{2})}^{2}} = \frac{25}{1}$

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