In Young's double slit experiment intensity of light emerging from each slit is $$I0$$. Wavelength of light used is λ, separation between the slits is d and separation between the slits and screen is D. P is a point on the screen where the resultant intensity is $$3I0$$. Then the minimum path difference between rays emerging from the slits at point P is

Question

In Young's double slit experiment intensity of light emerging from each slit is $$I0$$. Wavelength of light used is λ, separation between the slits is d and separation between the slits and screen is D. P is a point on the screen where the resultant intensity is $$3I0$$. Then the minimum path difference between rays emerging from the slits at point P is

Infinity Learn · Accepted Answer

At any point on the screen whose position is defined by the angle θ is $$I=Imcos2$$ϕ$$2=4I0cos2$$ϕ$$2At$$ point P, $$3I0=4I0cos2$$ϕ$$2$$⇒$$cos$$ϕ$$2=32$$⇒ϕ$$=60o$$∴ ϕ$$=2$$πλ×path $$difference=$$π$$3$$⇒dsinθ$$=$$λ$$6$$

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