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Q.

In a Young’s double slit experiment the intensity at a point where the path difference is λ/6 (λ being the wavelength of light used) is i. If I0 denotes the maximum intensity, I/I0  is equal to

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a

3 / 4

b

1 2

c

32

d

1 / 2

answer is A.

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Detailed Solution

Δx=λ/6ϕ=60oI=I0cos2602=I0Cos230=3I64               I I0=34
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In a Young’s double slit experiment the intensity at a point where the path difference is λ/6 (λ being the wavelength of light used) is i. If I0 denotes the maximum intensity, I/I0  is equal to