In Young's double slit experiment, an interference pattern is obtained on a screen by a light of wavelength 6000 A0 coming from the coherent sources S1 and S2 . At certain point p on the screen fifth dark fringe is formed. Then the path difference S1p−S2p in micron is
see full answer
Your Exam Success, Personally Taken Care Of
1:1 expert mentors customize learning to your strength and weaknesses – so you score higher in school , IIT JEE and NEET entrance exams.
An Intiative by Sri Chaitanya
a
1.5
b
4.5
c
5.4
d
2.7
answer is D.
(Unlock A.I Detailed Solution for FREE)
Best Courses for You
JEE
NEET
Foundation JEE
Foundation NEET
CBSE
Detailed Solution
Wavelength λ=6000 A0=6000×10−10 m Number of fringes n=5 Path difference Δx=(2n−1)λ2 =(2×5−1)6×10−72 =(10−1)6×10−72 =9×6×10−72=5.4 2 ∴ S1P−S2P=2.7 microns