First slide

Young's double slit Experiment

Question

In Young's double slit experiment, the length of band is 1 mm. The fringe width is 0 .021mm. The number of fringes is

Moderate

A

45
B

46
C

47
D

48

Solution

The number of fringes on either side of center C of the screen is
$n_{1} = \frac{distance}{fringe width} = \frac{AC}{β} = \frac{0 \cdot 5}{0 \cdot 021} \approx 23 Total number of fringes = 2 n_{1} + central bright fringe = 2 \times 23 + 1 = 47 S H O R T C U T Y = N β$

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