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Q.

In a Young’s double slit experiment, light of 500 nm is used to produce an interference pattern. When the distance between the slits is 0.05 mm, the angular width (in degree) of the fringes formed on the distance screen is close to :

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a

0.17º

b

0.07º

c

1.7º

d

0.57º

answer is D.

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Detailed Solution

angular fringe width=βD=λd=500×10−90.05×10−3=10−2rad=0.57deg
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