In Young's double slit experiment, the separation between the slit is halved and the distance between the slits and screen is doubled, The fringe width is
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a
unchanged
b
halved
c
double
d
quadrupled
answer is D.
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Detailed Solution
The fringe width β=λD2d and β′=λ(2D)dβ′=4βWhen the separation between the slits is halved and D is doubled, p becomes four times.