Q.

In Young’s double slit experiment, the separation between the slits is halved and the distance between the slits and the screen is doubled. The fringe width is :

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a

Unchanged

b

halved

c

doubled

d

quadrupled

answer is D.

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Detailed Solution

Fringe width β=λDdGiven : D is doubled and d is halvedβ'=λD'd'=λ2Dd2=4βThus, the fringe width is quadrupled.
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In Young’s double slit experiment, the separation between the slits is halved and the distance between the slits and the screen is doubled. The fringe width is :