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Q.

In a Young’s double slit experiment, the separation between the slits is 0.15 mm. In the experiment, a source of light of wavelength 589 nm is used and the interference pattern is observed on a screen kept 1.5 m away. The separation between the successive bright fringes on the screen is:

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a

5.9 mm

b

3.9 mm

c

4.9 mm

d

6.9 mm

answer is A.

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Detailed Solution

Fringe Width =β=λDd=589×10−9×1.50.15×10−3=5.9mm
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