In a Young’s double slit experiment, the separation between the two slits is2πmm and distance of the screen from the slits is 50 cm. If the wavelength of light used is 4000 Ac, then the angular position of first dark fringe is

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1.21∘

0.018∘

0.16∘

0.3∘

answer is B.

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Detailed Solution

θ=βD=λd⇒β=λDd The first dark fringe will be at half the fringe width from central maximum. α=θ2=12λd=124000×10−102×10−3π×180∘π=0.018∘

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