First slide

Coherent sources and their importance in interference

Question

In a Young’s double slit experiment, the slit separation is 1 mm and the screen is 1 m from the slit. For a monochromatic light of wavelength 500 nm, the distance of 3rd minima from the central maxima is

Easy

A

0.50 mm
B

1.25 mm
C

1.50 mm
D

1.75 mm

Solution

Distance of n^th minima from central bright fringe
$x_{n} = \frac{(2 n - 1) λD}{2 d} For n = 3 i.e. 3^{rd} minima x_{3} = \frac{(2 \times 3 - 1) \times 500 \times 10^{- 9} \times 1}{2 \times 1 \times 10^{- 3}} = \frac{5 \times 500 \times 10^{- 6}}{2} = 1 .25 \times 10^{- 3} m = 1 .25 mm .$

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