First slide

Young's double slit Experiment

Question

In Young's double slit experiment, the slits are 0.0 $λ = 300 \times 10^{- 10} m$ 5 mm apart and interference is observed on screen placed at a distance of 100 cm from the slits. It is found that 9^th bright fringe is at a distance of 9.0 mm from the second dark fringe from the center of the fringe pattern. The wavelength of light used is

Moderate

A

3000 A
B

300A
C

9000A
D

12000A

Solution

x = $\frac{9 λ D}{d} - \frac{3 λ D}{2 d}$
9 $\times 10^{- 3}$ m = $\frac{15 λ \times 1}{5 \times 10^{- 5}}$
$λ = 300 \times 10^{- 10} m$

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