In Young's double slit experiment, the slits are 0.0λ=300×10-10 m5 mm apart and interference is observed on screen placed at a distance of 100 cm from the slits. It is found that 9th bright fringe is at a distance of 9.0 mm from the second dark fringe from the center of the fringe pattern. The wavelength of light used is
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a
3000 A
b
300A
c
9000A
d
12000A
answer is B.
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Detailed Solution
x = 9 λDd-3λD2d9 ×10-3 m =15 λ×15×10-5λ=300×10-10 m